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  • Calcualting Optimal Site to Site Routing using pre-computed times between sites

    - by Idistic
    Assume that I have a number of sites (locations) and the time it takes to travel from each site to each site is pre-computed Example Data - Site to Site Pre-Calculated Times in minutes From Start Site To A 20 To B 15 To C 15 From Site A To B 10 To C 15 Site B To A 10 To C 20 Site C To A 15 To B 20 4 Sites is fairly simple, but what if the site set was say 1000 sites? Given a large site set What would the best approach be to quickly find the optimal routes from the start site while visiting every other site just once? Route Solutions from Start Site for 3 sites from a start site 1 A(20) B(10) C(20) = 50 2 A(20) C(15) B(20) = 55 3 B(15) A(10) C(15) = 40 4 B(15) C(20) A(15) = 50 5 C(15) A(15) B(10) = 40 6 C(15) B(20) A(10) = 45

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  • My ifelse statement's result depends on the actions for true/false?

    - by Antal
    Currently I am building a route for a truck to drive inside my netlogo-land. When the truck is next to the shop-patch where it should deliver, the truck needs to change its actions. However my if or ifelse statement does not seem to respond well and the answer depends on the output. With some tests: turtles ifelse ((patch (first dirx) (first diry)) = one-of neighbors4) [write "11"] [write "22"] "11" turtles ifelse ((patch (first dirx) (first diry)) = one-of neighbors4) [write "111"] [write "122"] "122" turtles ifelse (patch (first dirx) (first diry)) = one-of neighbors4 [write "111"] [write "122"] "122" turtles ifelse (patch (first dirx) (first diry)) = one-of neighbors4 [write "11"] [write "12"] "12" turtles ifelse (patch (first dirx) (first diry)) = one-of neighbors4 [write "11"] [write "22"] "11" Please note that during this time I do not move my truck, I use the command center to ask these questions (from turtle truck perspective). I am very confused about this. As the only thing I change is the action (what to write). This should not impact the true/false statement itself. Does anybody have any clue what is going on here and why the ifelse responds strange?

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  • is there a way to recursively merge then rebase all branches?

    - by yao jiang
    Let's say I have git repo like this: master webapp-1252 webapp-1285 webapp-1384 webapp-1433 webapp-1524 webapp-824 x_____jira_ x_webapp-11 x_webapp-11 x_webapp-11 z_____jira_ I've updated all of them and ready to push them all to svn or something. Then someone makes a quick change that would require me to basically go through all of them to merge etc. Is there a shortcut to go through all the branches I have here, merge them with whatever work that was fetched, then rebase them?

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  • Login as SYS user to Oracle 11g from .NET

    - by Jens Bannmann
    Using the Oracle Data Provider for .NET, my application connects to the database using the privileged SYS user. The connection string is as follows: Data Source=MyTnsName;User ID=sys;Password=MySysPassword;DBA Privilege=SYSDBA This works fine with Oracle 10, but Oracle 11 keeps complaining about an invalid username or password. I verified that the password is correct - other apps work fine with the same credentials. Note that for regular users (without the DBA Privilege part), connecting to Oracle 11 works perfectly. So, what's wrong? Update: This is not an issue with case sensitivity - when constructing the connection string, the password case is not altered by my code, and the password works fine with other, non-.NET-applications. I suspect that this might be caused by the Oracle 10 client I'm using to connect to the 11 database. Oracle states that the client is upward-compatible, the only drawback being that you cannot use some new features of the database. However, SYSDBA connections clearly are not a new Oracle 11 feature, and - again - a non-.NET-app (Keeptool Hora) can connect using the same setup. Any other ideas? Update 2: The problem persists when using an Oracle 11 client :-(

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  • Ajax, php, mysql not working mysql limit

    - by Hofmeister Ákos
    I have 3 files. list.php $articles = $mysqli->query("SELECT mainPictureBig, title, writer, writeDate, link FROM articles WHERE category=$this->category ORDER BY writeDate DESC LIMIT 0,10"); while($article = mysqli_fetch_row($articles)) { echo "<a href=\"".$this->url."/".$article[3]."/".$article[4]."\"><div id=\"listElement\"> <div id=\"listElementWallpaper\" style=\"background-image: url('category/img.jpg');\"></div> <div id=\"listElementContent\"><div id=\"listElementTitle\">".$article[1]."</div>".$this->giveWriter($article[2]).", ".$this->giveDate($article[3])."</div> </div></a>"; } $maximumElements=ceil($numberOfContent / 10) * 10; It's working, so there is no problem, it lists the first 10 elements from the sql table, and i got the $numberOfCOntent part also. Than i have a button: echo "<div id=\"listMore\"><div id=\"buttonOne\" onclick=\"listMore($this->category,$maximumElements)\">Load more</div></div>"; There is also no problem, i load the .js file, and it looks like: var from = 10; function listMore(categoryId, maximum) { $( "#listMore" ).slideUp( 200, function() { $( "#listMore" ).html("<center>Loading..</center>"); $( "#listMore" ).slideDown( 500, function() { $.post( "http://localhost/ajax.php", {type: "listMore", id: categoryId, sqlFrom: from} ) .done(function( elements ) { $("#listBody").append( elements ); if(maximum > from+10) { from = from+10; $( "#listMore" ).slideUp(200, function() { $( "#listMore" ).html("<div id=\"buttonOne\" onclick=\"listMore("+categoryId+","+maximum+")\">Load more</div>"); $( "#listMore" ).slideDown(200); }); } else $( "#listMore" ).slideUp(200); }); }); }); } And it's also working, and the problem is in the PHP file. As you can see, i'm sending an integer the "from" variable, the PHP file: $articles = $mysqli->query("SELECT mainPictureBig, title, writer, writeDate, link FROM articles WHERE category=$id ORDER BY writeDate DESC LIMIT $from,10"); It's also working, but not loading the next 10, only the next 9. So it skips the very next row and loads the rows only after the very first, so only 9. I tried to write here only the important part of the code, so i skipped some echo part etc. Any idea?

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  • Converting MySQL Resultset from Rows to Columns

    - by gms8994
    I have output from a select like this: 04:47:37> select * from attributes left outer join trailer_attributes on attributes.id = trailer_attributes.attribute_id; +----+--------------+----------+-----------+------------+--------------+-----------------+ | id | name | datatype | list_page | trailer_id | attribute_id | attribute_value | +----+--------------+----------+-----------+------------+--------------+-----------------+ | 1 | Make | text | 1 | 1 | 1 | Apple | | 1 | Make | text | 1 | 2 | 1 | sdfg | | 2 | Year | number | 1 | 1 | 2 | 2009 | | 2 | Year | number | 1 | 2 | 2 | sdfg | | 3 | Type | text | 0 | 1 | 3 | iPhone | | 3 | Type | text | 0 | 2 | 3 | sdfg | | 4 | Axles | text | 0 | 1 | 4 | asdf | | 4 | Axles | text | 0 | 2 | 4 | sdfg | | 7 | Size | text | 0 | 1 | 7 | asd1 | | 7 | Size | text | 0 | 2 | 7 | sdfg | | 8 | Frame | text | 0 | 1 | 8 | | | 8 | Frame | text | 0 | 2 | 8 | sdfg | | 9 | Height | text | 0 | 1 | 9 | | | 9 | Height | text | 0 | 2 | 9 | sdfg | | 10 | Dollies | text | 0 | 1 | 10 | | | 10 | Dollies | text | 0 | 2 | 10 | sdfg | | 11 | Tires/Wheels | text | 0 | 1 | 11 | | | 11 | Tires/Wheels | text | 0 | 2 | 11 | sdfg | | 12 | Condition | text | 1 | 1 | 12 | New | | 12 | Condition | text | 1 | 2 | 12 | sdfg | | 13 | Title | text | 0 | 1 | 13 | | | 13 | Title | text | 0 | 2 | 13 | sdfg | +----+--------------+----------+-----------+------------+--------------+-----------------+ I want to convert it to something more along the lines of: id, Make, Year, Type, Axles, Size, Frame (etc) 1, Apple, 2009, iPhone, ..... 2, sdfg, sdfg, sdfg, ..... Any suggestions?

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  • Table transformation / field parsing in PL/SQL

    - by IMHO
    I have de-normalized table, something like CODES ID | VALUE 10 | A,B,C 11 | A,B 12 | A,B,C,D,E,F 13 | R,T,D,W,W,W,W,W,S,S The job is to convert is where each token from VALUE will generate new record. Example: CODES_TRANS ID | VALUE_TRANS 10 | A 10 | B 10 | C 11 | A 11 | B What is the best way to do it in PL/SQL without usage of custom pl/sql packages, ideally with pure SQL? Obvious solution is to implement it via cursors. Any ideas?

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  • tracd server problems

    - by deddihp
    Hello, I got the following error while accessing tracd server, what's going on ? Thanks. [oke@localhost Trac-0.11.7]$ sudo tracd -p 8000 /home/deddihp/trac/ Server starting in PID 5082. Serving on 0.0.0.0:8000 view at http://127.0.0.1:8000/ ---------------------------------------- Exception happened during processing of request from ('127.0.0.1', 47804) Traceback (most recent call last): File "/usr/lib/python2.6/SocketServer.py", line 558, in process_request_thread self.finish_request(request, client_address) File "/usr/lib/python2.6/SocketServer.py", line 320, in finish_request self.RequestHandlerClass(request, client_address, self) File "/usr/lib/python2.6/SocketServer.py", line 615, in __init__ self.handle() File "/usr/lib/python2.6/BaseHTTPServer.py", line 329, in handle self.handle_one_request() File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 194, in handle_one_request gateway.run(self.server.application) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/wsgi.py", line 94, in run response = application(self.environ, self._start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/standalone.py", line 100, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/site-packages/Trac-0.11.7-py2.6.egg/trac/web/main.py", line 346, in dispatch_request locale.setlocale(locale.LC_ALL, environ['trac.locale']) File "/usr/lib/python2.6/locale.py", line 513, in setlocale return _setlocale(category, locale) Error: unsupported locale setting ----------------------------------------

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  • Mysql select - improve performances

    - by realshadow
    Hey, I am working on an e-shop which sells products only via loans. I display 10 products per page in any category, each product has 3 different price tags - 3 different loan types. Everything went pretty well during testing time, query execution time was perfect, but today when transfered the changes to the production server, the site "collapsed" in about 2 minutes. The query that is used to select loan types sometimes hangs for ~10 seconds and it happens frequently and thus it cant keep up and its hella slow. The table that is used to store the data has approximately 2 milion records and each select looks like this: SELECT * FROM products_loans WHERE KOD IN("X17/Q30-10", "X17/12", "X17/5-24") AND 369.27 BETWEEN CENA_OD AND CENA_DO; 3 loan types and the price that needs to be in range between CENA_OD and CENA_DO, thus 3 rows are returned. But since I need to display 10 products per page, I need to run it trough a modified select using OR, since I didnt find any other solution to this. I have asked about it here, but got no answer. As mentioned in the referencing post, this has to be done separately since there is no column that could be used in a join (except of course price and code, but that ended very, very badly). Here is the show create table, kod and CENA_OD/CENA_DO very indexed via INDEX. CREATE TABLE `products_loans` ( `KOEF_ID` bigint(20) NOT NULL, `KOD` varchar(30) NOT NULL, `AKONTACIA` int(11) NOT NULL, `POCET_SPLATOK` int(11) NOT NULL, `koeficient` decimal(10,2) NOT NULL default '0.00', `CENA_OD` decimal(10,2) default NULL, `CENA_DO` decimal(10,2) default NULL, `PREDAJNA_CENA` decimal(10,2) default NULL, `AKONTACIA_SUMA` decimal(10,2) default NULL, `TYP_VYHODY` varchar(4) default NULL, `stage` smallint(6) NOT NULL default '1', PRIMARY KEY (`KOEF_ID`), KEY `CENA_OD` (`CENA_OD`), KEY `CENA_DO` (`CENA_DO`), KEY `KOD` (`KOD`), KEY `stage` (`stage`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 And also selecting all loan types and later filtering them trough php doesnt work good, since each type has over 50k records and the select takes too much time as well... Any ides about improving the speed are appreciated. Edit: Here is the explain +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ | 1 | SIMPLE | products_loans | range | CENA_OD,CENA_DO,KOD | KOD | 92 | NULL | 190158 | Using where | +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ I have tried the combined index and it improved the performance on the test server from 0.44 sec to 0.06 sec, I cant access the production server from home though, so I will have to try it tomorrow.

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  • Sorting a list of variable length integers delimited by decimal points...

    - by brewerdc
    Hey guys, I'm in need of some help. I have a list of delimited integer values that I need to sort. An example: Typical (alpha?) sort: 1.1.32.22 11.2.4 2.1.3.4 2.11.23.1.2 2.3.7 3.12.3.5 Correct (numerical) sort: 1.1.32.22 2.1.3.4 2.3.7 2.11.23.1.2 3.12.3.5 11.2.4 I'm having trouble figuring out how to setup the algorithm to do such a sort with n number of decimal delimiters and m number of integer fields. Any ideas? This has to have been done before. Let me know if you need more information. Thanks a bunch! -Daniel

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  • issue when outputting an http:// address in a sub-array with json and php

    - by Patrick
    Im trying to achieve an output like this {"status":"ok","0":{"id":"11","title":"digg","url":"http://www.digg.com"}} but instead i am getting this {"status":"ok","0":{"id":"11","title":"digg","url":"http:\/\/www.digg.com"}} this is the php code im using to generate the json $links = array('id'=>'11','title'=>'digg','url'=>"http://www.digg.com"); $msg = array('status'=>'ok',$links); echo json_encode($msg); any idea what is causing this?

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  • In SQL, what does Group By mean without Count(*), or Sum(), Max(), avg(), ..., and what are some use

    - by Jian Lin
    In SQL, if we use Group By without Count(*) or Sum(), etc, then the result is as follows: mysql> select * from sentGifts; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | | 2 | 2010-04-24 | 123 | 4568 | 2010-04-24 01:56:04 | 100 | | 3 | 2010-04-24 | 123 | NULL | NULL | 1 | | 4 | 2010-04-24 | NULL | 111 | 2010-04-24 03:10:42 | 2 | | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 6 | 2010-04-24 | 11 | 222 | 2010-04-24 03:54:49 | 6 | | 7 | 2010-04-24 | 1 | 2 | 2010-04-24 03:58:45 | 6 | +--------+------------+--------+------+---------------------+--------+ 7 rows in set (0.00 sec) mysql> select *, count(*) from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+----------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | count(*) | +--------+------------+--------+------+---------------------+--------+----------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | 1 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | 6 | +--------+------------+--------+------+---------------------+--------+----------+ 2 rows in set (0.00 sec) mysql> select * from sentGifts group by whenSent; +--------+------------+--------+------+---------------------+--------+ | sentID | whenSent | fromID | toID | trytryWhen | giftID | +--------+------------+--------+------+---------------------+--------+ | 5 | 2010-03-03 | 11 | 22 | 2010-03-03 00:00:00 | 6 | | 1 | 2010-04-24 | 123 | 456 | 2010-04-24 01:52:20 | 100 | +--------+------------+--------+------+---------------------+--------+ 2 rows in set (0.00 sec) Only 1 row is returned per "group". What does it mean when there is no "Count(*)", etc when using "Group By", and what are it uses? thanks.

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  • Weblogic server lib VS instance libext

    - by Sebastien Lorber
    Hello, I use weblogic 10. Its provide an Oracle JDBC driver 10.2.0.2 (in the server/lib on weblogic home). Actually someone at work put a long time ago a 10.2.0.3 driver in instance libext folder. But in production we got a jdbc driver stack (nullpointer :O) and by reverse engineering it seems we are using driver 10.2.0.2. We know that we could change the driver in the server/lib of weblogic but i want to understand. Isn't libext supposed to override server libs like META-INF libs override libext? By the way we are in a strange situation: - We have 2 EAR, and for the exact same treatment in those 2, one will sometime throw the oracle driver nullpointer while the other doesn't - I wonder if one ear isn't using 10.2.0.2 while the other is using 10.2.0.3 (i saw a bug fixed that could fit to our problem for this version). - I need to look better but at first sight both ear use the exact same datasource set in weblogic JNDI resources Any idea?

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • A python code to convert a number from any base to the base of 10 giving errors . What is wrong with this code?

    - by mekasperasky
    import math def baseencode(number, base): ##Converting a number of any base to base10 if number == 0: return '0' for i in range(0,len(number)): if number[i]!= [A-Z]: num = num + number[i]*pow(i,base) else : num = num + (9 + ord(number[i])) *pow(i,base) return num a = baseencode('20',5) print a Errors I get are Traceback (most recent call last): File "doubtrob.py", line 19, in <module> a = baseencode('20',5) File "doubtrob.py", line 13, in baseencode if number[i]!= [A-Z]: NameError: global name 'A' is not defined

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  • How to display multiple categories and products underneath each category?

    - by shin
    Generally there is a category menu and each link to a category page where shows all the items under that category. Now I need to show all the categories and products underneath with PHP/MySQL in the same page. So it will be like this. Category 1 description of category 1 item 1 item 2 .. Category 2 description of category 2 item 5 item 6 .. Category 3 description of category 3 item 8 item 9 ... ... I have category and product table in my database. But I am not sure how to proceed. CREATE TABLE IF NOT EXISTS `omc_product` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `thumbnail` varchar(255) NOT NULL, `image` varchar(255) NOT NULL, `product_order` int(11) DEFAULT NULL, `class` varchar(255) DEFAULT NULL, `grouping` varchar(16) DEFAULT NULL, `status` enum('active','inactive') NOT NULL, `category_id` int(11) NOT NULL, `featured` enum('none','front','webshop') NOT NULL, `other_feature` enum('none','most sold','new product') NOT NULL, `price` float(7,2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; CREATE TABLE IF NOT EXISTS `omc_category` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `status` enum('active','inactive') NOT NULL, `parentid` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; I will appreciate your help. Thanks in advance.

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  • Find all html characters in drop-down option text and replace them via jQuery

    - by Jon Harding
    I have a dropdown menu that pulls in text from a database column. The database column can include HTML mark-up. In the drop-down I obviously don't need that in the text. I am working on some jquery and it partially accomplished what I'm looking for. However, it seems to only be replacing the first instance of each character $('select option').each(function() { this.text = this.text.replace('&nbsp;', ' '); this.text = this.text.replace('<div>', '' ); this.text = this.text.replace('</div>', '' ); }); Here is the HTML for the drop-down: <select name="ctl00$SubPageBody$ClassList" id="ctl00_SubPageBody_ClassList"> <option value="196">Four Week Series: July 19, 2012, 11:00am-12:00pm&<div>July 26, 2012, 11:00am-12:00pm&nbsp;</div><div>August 2, 2012, 11:00am-12:00pm</div><div>August 9, 2012, 11:00am-12:00pm</div></option> </select>

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  • Can someone help with big O notation?

    - by Dann
    void printScientificNotation(double value, int powerOfTen) { if (value >= 1.0 && value < 10.0) { System.out.println(value + " x 10^" + powerOfTen); } else if (value < 1.0) { printScientificNotation(value * 10, powerOfTen - 1); } else // value >= 10.0 { printScientificNotation(value / 10, powerOfTen + 1); } } I understand how the method goes but I cannot figure out a way to represent the method. For example, if value was 0.00000009 or 9e-8, the method will call on printScientificNotation(value * 10, powerOfTen - 1); eight times and System.out.println(value + " x 10^" + powerOfTen); once. So the it is called recursively by the exponent for e. But how do I represent this by big O notation? Thanks!

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  • What is the display list in Flash 10? Array? Linked list?

    - by Typeoneerror
    I'm working on a game that has many elements on stage, so I'm looking to optimize my loops. I know that Vector is faster than looping an array, but I'm also in some cases using: while (i < numChildren) getChildAt(i) ...to update sprites. My question is when I use getChildAt, is that accessing an Array or Vector or linked list or other? Should I instead store references to my objects in a Vector and loop through that instead?

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  • Better data-structure design

    - by Tempname
    Currently in my application I have a single table that is giving me a bit of trouble. The issue at hand is I have a value object that is mapped to this table. When the data is returned to me as an array of value objects, I have to then loop through this array and begin my recursion by matching the ParentID to parent ObjectID's. The column ParentID is either null (acts a parent) or it holds the value of an ObjectID. I know there has to be a better way to create this data structure so that I do not have to do recursive loops to match ParentID's with their ObjectID's. Any help with this is greatly appreciated. Here is the table in describe form: +----------------+------------------+------+-----+---------------------+-----------------------------+ | Field | Type | Null | Key | Default | Extra | +----------------+------------------+------+-----+---------------------+-----------------------------+ | ObjectID | int(11) unsigned | NO | PRI | NULL | auto_increment | | ObjectHeight | decimal(6,2) | NO | | NULL | | | ObjectWidth | decimal(6,2) | NO | | NULL | | | ObjectX | decimal(6,2) | NO | | NULL | | | ObjectY | decimal(6,2) | NO | | NULL | | | ObjectLabel | varchar(255) | NO | | NULL | | | TemplateID | int(11) unsigned | NO | MUL | NULL | | | ObjectTypeID | int(11) unsigned | NO | MUL | NULL | | | ParentID | int(11) unsigned | YES | MUL | NULL | | | CreationDate | datetime | YES | | 0000-00-00 00:00:00 | | | LastModifyDate | timestamp | YES | | NULL | on update CURRENT_TIMESTAMP | +----------------+------------------+------+-----+---------------------+-----------------------------+e

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  • Divide and Conquer Algo to find maximum difference between two ordered elements

    - by instance
    Given an array arr[] of integers, find out the difference between any two elements such that larger element appears after the smaller number in arr[]. Examples: If array is [2, 3, 10, 6, 4, 8, 1, 7] then returned value should be 8 (Diff between 10 and 2). If array is [ 7, 9, 5, 6, 3, 2 ] then returned value should be 2 (Diff between 7 and 9) My Algorithm: I thought of using D&C algorithm. Explanation 2, 3, 10, 6, 4, 8, 1, 7 then 2,3,10,6 and 4,8,1,7 then 2,3 and 10,6 and 4,8 and 1,7 then 2 and 3 10 and 6 4 and 8 1 and 7 Here as these elements will remain in same order, i will get the maximum difference, here it's 6. Now i will move back to merege these arrays and again find the difference between minimum of first block and maximum of second block and keep doing this till end. I am not able to implement this in my code. can anyone please provide a pseudo code for this?

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  • Implications of trying to double free memory space in C

    - by SidNoob
    Here' my piece of code: #include <stdio.h> #include<stdlib.h> struct student{ char *name; }; int main() { struct student s; s.name = malloc(sizeof(char *)); // I hope this is the right way... printf("Name: "); scanf("%[^\n]", s.name); printf("You Entered: \n\n"); printf("%s\n", s.name); free(s.name); // This will cause my code to break } All I know is that dynamic allocation on the 'heap' needs to be freed. My question is, when I run the program, sometimes the code runs successfully. i.e. ./struct Name: Thisis Myname You Entered: Thisis Myname I tried reading this I've concluded that I'm trying to double-free a piece of memory i.e. I'm trying to free a piece of memory that is already free? (hope I'm correct here. If Yes, what could be the Security Implications of a double-free?) While it fails sometimes as its supposed to: ./struct Name: CrazyFishMotorhead Rider You Entered: CrazyFishMotorhead Rider *** glibc detected *** ./struct: free(): invalid next size (fast): 0x08adb008 *** ======= Backtrace: ========= /lib/tls/i686/cmov/libc.so.6(+0x6b161)[0xb7612161] /lib/tls/i686/cmov/libc.so.6(+0x6c9b8)[0xb76139b8] /lib/tls/i686/cmov/libc.so.6(cfree+0x6d)[0xb7616a9d] ./struct[0x8048533] /lib/tls/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb75bdbd6] ./struct[0x8048441] ======= Memory map: ======== 08048000-08049000 r-xp 00000000 08:01 288098 /root/struct 08049000-0804a000 r--p 00000000 08:01 288098 /root/struct 0804a000-0804b000 rw-p 00001000 08:01 288098 /root/struct 08adb000-08afc000 rw-p 00000000 00:00 0 [heap] b7400000-b7421000 rw-p 00000000 00:00 0 b7421000-b7500000 ---p 00000000 00:00 0 b7575000-b7592000 r-xp 00000000 08:01 788956 /lib/libgcc_s.so.1 b7592000-b7593000 r--p 0001c000 08:01 788956 /lib/libgcc_s.so.1 b7593000-b7594000 rw-p 0001d000 08:01 788956 /lib/libgcc_s.so.1 b75a6000-b75a7000 rw-p 00000000 00:00 0 b75a7000-b76fa000 r-xp 00000000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fa000-b76fc000 r--p 00153000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fc000-b76fd000 rw-p 00155000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fd000-b7700000 rw-p 00000000 00:00 0 b7710000-b7714000 rw-p 00000000 00:00 0 b7714000-b7715000 r-xp 00000000 00:00 0 [vdso] b7715000-b7730000 r-xp 00000000 08:01 788898 /lib/ld-2.11.1.so b7730000-b7731000 r--p 0001a000 08:01 788898 /lib/ld-2.11.1.so b7731000-b7732000 rw-p 0001b000 08:01 788898 /lib/ld-2.11.1.so bffd5000-bfff6000 rw-p 00000000 00:00 0 [stack] Aborted So why is it that my code does work sometimes? i.e. the compiler is not able to detect at times that I'm trying to free an already freed memory. Has it got to do something with my stack/heap size?

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  • Spring @Value annotation not using defaults when property is not present

    - by garyj
    Hi All I am trying to use @Value annotation in the parameters of a constructor as follows: @Autowired public StringEncryptor( @Value("${encryptor.password:\"\"}") String password, @Value("${encryptor.algorithm:\"PBEWithMD5AndTripleDES\"}") String algorithm, @Value("${encryptor.poolSize:10}") Integer poolSize, @Value("${encryptor.salt:\"\"}") String salt) { ... } When the properties file is present on the classpath, the properties are loaded perfectly and the test executes fine. However when I remove the properties file from the classpath, I would have expected that the default values would have been used, for example poolSize would be set to 10 or algorithm to PBEWithMD5AndTripleDES however this is not the case. Running the code through a debugger (which would only work after changing @Value("${encryptor.poolSize:10}") Integer poolSize to @Value("${encryptor.poolSize:10}") String poolSize as it was causing NumberFormatExceptions) I find that the defaults are not being set and the parameters are in the form of: poolSize = ${encryptor.poolSize:10} or algorithm = ${encryptor.algorithm:"PBEWithMD5AndTripleDES"} rather than the expected poolSize = 10 or algorithm = "PBEWithMD5AndTripleDES" Based on SPR-4785 the notation such as ${my.property:myDefaultValue} should work. Yet it's not happening for me! Thank you

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  • iteration on numbers with no 2 same digits

    - by rahmivolkan
    I dont know if it is asked (I couldn't find any). I want to iterate on this kind of numbers implemented on array; int a[10]; int i = 0; for( ; i < 10; i++ ) a[i] = i+1; now the array has "1 2 3 4 5 6 7 8 9 10" and I want to get "1 2 3 4 5 6 7 8 10 9" and then "1 2 3 4 5 6 7 9 8 10" "1 2 3 4 5 6 7 9 10 8" . . . . I tried to get an algorithm but I couldn't figure it out. Is there an easy way to implement "next" iterator for this kind of problems? Thanks in advance

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  • TableView reloading problem

    - by abdulsamad
    Hi All, i am in a very serious problem of tableview reloading. i have two option in my tableview 1) show next 10 Results 2) show previos 10 results I wanna show only 50 results at a time in my table view. when table is populated with 50 results after that on pressing "show next 10 results" the results from 1-10 are removed and results from 51-60 are now displayed and hence i have the total results in my table view from 11-60. As the total # of results remain 50 hence i have the cells with their identifier from 1-50 and now they are not nil. So i also have to code in else block of the condition if(cell == nil) { } else{ Have to write the same code as in if. } Now my cells are properly reloading on clicking "show next 10" and on clicking "show previous 10" but the problem is that because of the code in else block my cells are also reloaded when the user scrolls the table-view. Kindly give some good suggestion what should i do to get out from this situation.

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